A 10-substring of a number is a substring of its digits that sum up to 10.
For example, the 10-substrings of the number 3523014 are:
3523014, 3523014, 3523014, 3523014
Write a python function, find_ten_substring(num_str) which accepts a string and returns the list of 10-substrings of that string.
Handle the possible errors in the code written inside the function.
For example, the 10-substrings of the number 3523014 are:
3523014, 3523014, 3523014, 3523014
Write a python function, find_ten_substring(num_str) which accepts a string and returns the list of 10-substrings of that string.
Handle the possible errors in the code written inside the function.
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| #PF-Assgn-41 | |
| def find_ten_substring(num_str): | |
| m=[] | |
| l=[] | |
| for i in range(0,len(num_str)): | |
| for j in range(i,len(num_str)): | |
| m.append(num_str[i:j+1]) | |
| for k in set(m): | |
| s=0 | |
| for b in range(0,len(k)): | |
| s=s+int(k[b]) | |
| if(s==10 and b+1==len(k)): | |
| l.append(k) | |
| return l | |
| #Remove pass and write your logic here | |
| num_str="2825302" | |
| print("The number is:",num_str) | |
| result_list=find_ten_substring(num_str) | |
| print(result_list) |
i'm trying to solve the same problem but couldnt understand the logic in the code.
ReplyDeleteUse the following code instead.
DeleteHere, "-" shows the identation spaces.
def find_ten_substring(num_str):
-result_list=[]
--for i in range(0,len(num_str)):
---sum=0
---num=""
---for j in range (i,len(num_str)):
----sum=sum+int(num_str[j])
----if sum<10:
-----num=num+num_str[j]
----elif sum==10:
-----num=num+num_str[j]
-----result_list.append(num)
----else:
-----break
--return result_list
num_str="2825302"
print("The number is:",num_str)
result_list=find_ten_substring(num_str)
print(result_list)
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ReplyDelete
ReplyDeletedef find_ten_substring(num_str):
flag=0
sum=0
list=[]
item=""
tuple=()
for i in range(0,len(num_str)):
sum=sum+int(num_str[i])
item+=num_str[i]
if sum==10:
flag+=1
#print(flag,"flag")
list.append(item)
print(list)
return find_ten_substring(num_str[flag:])
break
else:
continue
num_str="2825302"
print("The number is:",num_str)
result_list=find_ten_substring(num_str)
//this can be a reduced code
ReplyDeletedef find_ten_substring(s):
L=[];sum=0;m=[]
for i in range(0,len(s)):
sum=0
for j in range(i,len(s)):
sum=sum+int(s[j])
if(sum==10):
L.append(s[i:j+1])
if(sum>10):
break
return L
num_str="3523014"
print("The number is:",num_str)
result_list=find_ten_substring(num_str)
print(result_list)