The below function is written to check whether a given three digit number is an Armstrong number. Hint: An “Armstrong number” is an n-digit number that is equal to the sum of the nth powers of its individual digits. Example: 371 is an Armstrong number as 371 = 3^3 +7^3+ 1^3

The below function is written to check whether a given three digit number is an Armstrong number.

Hint: An “Armstrong number” is an n-digit number that is equal to the sum of the nth powers of its individual digits.
Example: 371 is an Armstrong number as 371 = 3^3 +7^3+ 1^3

Source:

	'''
	Created on 24-Aug-2019
	@author: Anonymous
	'''
	#PF-Tryout
	def find_armstrong(number):
	temp=0
	x=number #
	while(number!=0):
	remainder=number%10
	# This Statement changing the value of number variable so
	number=number//10
	# For keeping original Number we took it in a variable named a "x"
	temp+=(remainder*remainder*remainder)
	if(x==temp):
	return True
	return False
	number=371
	if(find_armstrong(number)):
	print(number,"is an Armstrong number")
	else:
	print(number,"is not an Armstrong number")

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